Top-Seeded Bears Face Washington in Final of Pac-10 Tournament
March 13, 2010
LOS ANGELES -
California Golden Bears (23-9) vs. Washington Huskies (23-9)
Saturday, March 13, 3 p.m., Staples Center, Los Angeles, Calif.
Radio: KFRC 1550 AM TV: CBS
Entering the Pac-10 Tournament as the No. 1 seed for the first time, regular-season Pac-10 champion California is riding a six-game winning streak into the final of the Pac-10 Tournament. The Golden Bears will play Washington Saturday at 3 p.m. at Staples Center in Los Angeles.
This is Cal's second appearance in the final of the Pac-10 Tournament. The Bears lost to UCLA in the 2006 finale, 71-52.
The Bears were able to get past UCLA in the semifinals, 85-72, on Friday behind 24 points from Randle and 20 from All-Pac-10 second-teamer Theo Robertson. The Bears shooting percentage of 60.0 was a season high, led by Randle who shot 7-for-11 from the field. In their first two games on the tournament, Cal has shot a combined 63-for-111 (54.0 percent). Cal has also shot 17-for-36 (47.2 percent) from three-point distance.
This will be the second meeting in the Pac-10 Tournament between Cal and Washington. These two teams met in the first round of the 2008 tournament, with the Bears winning, 84-81.
Cal most recently won a conference crown in 1960 when the Bears captured the last of four straight Athletic Association of Western Universities (AAWU) crowns. Cal finished that year with a 28-2 overall record and 11-1 league mark, reaching the NCAA championship game before falling to Ohio State.
A strong free-throw shooting team all season, this year's Cal squad currently ranks No.12 in the nation at 75.3 percent, with Randle second in the country indivudally at 93.3 percent - the best single-season percentage in school history and the second best in Pac-10 history.
The Bears have won nine of their last 10 games, each by at least 10 points. This is Cal's first six-game winning streak since they enjoyed a nine-game winning streak last season.